Extraje datos de un sitio web, terminé con una lista que incluye la etiqueta span y los datos que necesito, probé algunos ajustes pero no puedo encontrar el método adecuado. Quiero eliminar la etiqueta span y recuperar solo el nombre y la información del móvil.
[<span class="a-size-medium a-color-base a-text-normal">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)</span>]
Quiero salida de la siguiente manera:
[ Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey,Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty),Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)]
La lista anterior solo contiene algunos elementos de mi lista principal. Eliminaré varias entradas más tarde.
1
Arpit Vasava
11 may. 2019 a las 11:06
3 respuestas
La mejor respuesta
Extraiga cada elemento de la lista y cárguelo en BeautifulSoup, seleccione todas las etiquetas de extensión. Si tiene una lista real de cadenas, espero que encierre cadenas. Agregar a un conjunto para eliminar duplicados.
from bs4 import BeautifulSoup as bs
aList = ['<span class="a-size-medium a-color-base a-text-normal">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)</span>, <span class="a-size-medium a-color-base a-text-normal">Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)</span>']
for i in aList:
soup = bs(i, 'lxml')
text = [item.text for item in soup.select('span')] #list
print(text)
text = ','.join([item.text for item in soup.select('span')]) #comma separated string
print(text)
0
QHarr
11 may. 2019 a las 09:38
s = 'Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty),Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty),Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty), Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black), Huawei Honor 8X (64GB + 4GB RAM) 6.5" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)'
sp = s.split(",")
gl = []
for sk in sp:
gl.append(sk)
from collections import OrderedDict
res = list(OrderedDict.fromkeys(gl))
print (res)
(Como cada elemento se repite después de a, lo usé como separador. Asegúrese de que, después de todo, la alineación sea correcta) Espero que ayude
0
j.doe
12 may. 2019 a las 05:06
¿Te refieres a algo como esto?
txt = "<span class=\"a-size-medium a-color-base a-text-normal\">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class=\"a-size-medium a-color-base a-text-normal\">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class=\"a-size-medium a-color-base a-text-normal\">Huawei Mate SE Factory Unlocked 5.93” - 4GB/64GB Octa-core Processor| 16MP + 2MP Dual Camera| GSM Only |Grey (US Warranty)</span>, <span class=\"a-size-medium a-color-base a-text-normal\">Huawei Honor 8X (64GB + 4GB RAM) 6.5\" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)</span>, <span class=\"a-size-medium a-color-base a-text-normal\">Huawei Honor 8X (64GB + 4GB RAM) 6.5\" HD 4G LTE GSM Factory Unlocked Smartphone - International Version No Warranty JSN-L23 (Black)</span>"
x = txt.split(", ")
mylist = list(dict.fromkeys(x))
list = []
for val in mylist:
if ("</span>" in val):
val = val[:val.rfind("</span>")]
if ("<span class=\"a-size-medium a-color-base a-text-normal\">" in val):
val = val[len("<span class=\"a-size-medium a-color-base a-text-normal\">"):]
list.append(val)
1
mopebi
28 may. 2019 a las 07:45